Iron reacts with chlorine to form iron(III) chloride.


2Fe + 3Cl2 → 2FeCl3


What mass (in grams) of chlorine gas is needed to react with 251 grams of iron?

Select one:

a.
71 grams


b.
392 grams


c.
479 grams


d.
622 grams

Answers

Answer 1

The mass (in grams) of chlorine gas is needed to react with 251 grams of iron is 479 grams. Option C.

To determine the mass of chlorine gas needed to react with 251 grams of iron, we need to use the stoichiometry of the balanced chemical equation:

2Fe + 3Cl2 → 2FeCl3

From the balanced equation, we can see that 2 moles of iron (Fe) react with 3 moles of chlorine gas (Cl2) to produce 2 moles of iron(III) chloride (FeCl3).

To calculate the mass of chlorine gas, we can follow these steps:

Step 1: Convert the given mass of iron (Fe) to moles.

Using the molar mass of iron (Fe), which is approximately 55.85 g/mol, we can calculate the number of moles of iron:

moles of Fe = mass of Fe / molar mass of Fe

moles of Fe = 251 g / 55.85 g/mol

moles of Fe ≈ 4.5 mol (rounded to one decimal place)

Step 2: Use the mole ratio from the balanced equation to find the moles of chlorine gas (Cl2) needed.

From the balanced equation, we know that 2 moles of Fe react with 3 moles of Cl2. Therefore, the moles of Cl2 can be calculated as:

moles of Cl2 = (moles of Fe / 2) * 3

moles of Cl2 = (4.5 mol / 2) * 3

moles of Cl2 ≈ 6.75 mol (rounded to two decimal places)

Step 3: Convert the moles of chlorine gas to grams.

Using the molar mass of chlorine gas (Cl2), which is approximately 70.90 g/mol, we can calculate the mass of chlorine gas:

mass of Cl2 = moles of Cl2 * molar mass of Cl2

mass of Cl2 = 6.75 mol * 70.90 g/mol

mass of Cl2 ≈ 479 grams (rounded to the nearest whole number) Option C is correct.

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Related Questions

Element X appears on the periodic table as X10 22.076. How many electrons would you expect to find in one atom of this element?​

Answers

The number of electrons  you would expect to find in one atom of this element is 10.

What is the atomic number of an element?

The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).

Since the atom is electrically neutral, the number of protons in the atom must be equal to the number of electrons in the atom.

For an atom represented as X10, with an atomic number of 10, the number of electrons in the atom is simply 10.

Thus, if  an element X appears on the periodic table as X10 22.076, the number of electrons  you would expect to find in one atom of this element is 10.

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98.6 grams of sodium hydroxide reacts with 90.5 grams of sulfuric acid to form sodium sulfate and water. How many grams of sodium sulfate are formed? Determine the percent yield if 122.4g of sodium sulfate are experimentally found.

Answers

1. The mass of sodium sulfate, Na₂SO₄ formed from the reaction is 131.13 g

2. The percentage yield obtained from the reaction is 93.3%

1. How do i determine the mass of sodium sulfate formed?

We shall begin by obtaining the limiting reactant. This obtained as follow

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

Molar mass of NaOH = 40 g/molMass of NaOH from the balanced equation = 2 × 40 = 80 g Molar mass of H₂SO₄ = 98 g/molMass of H₂SO₄ from the balanced equation = 1 × 98 = 98 g

From the balanced equation above,

80 g of NaOH reacted with 98 g of H₂SO₄

Therefore,

98.6 g of NaOH will react with = (98.6 × 98) / 80 = 120.785 g of H₂SO₄

Since a higher amount (i.e 120.785 g) of H₂SO₄ than what was given (i.e 80.5 g) is needed to react with 98.6 g of NaOH, thus, the limiting reactant is H₂SO₄

Finally, we shall determine mass of sodium sulfate, Na₂SO₄ formed. Details below:

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

Molar mass of H₂SO₄ = 98 g/molMass of H₂SO₄ from the balanced equation = 1 × 98 = 98 gMolar mass of Na₂SO₄ = 142 g/molMass of Na₂SO₄ from the balanced equation = 1 × 142 = 142 g

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 142 g of Na₂SO₄

Therefore,

90.5 g of H₂SO₄ will react to produce = (90.5 × 142) / 98 = 131.13 g of Na₂SO₄

Thus, the mass of mass of sodium sulfate, Na₂SO₄ formed is 131.13 g

2. How do i determine the percentage yield?

The percentage yield obtained can be obtained as follow:

Actual yield of sodium sulfate = 122.4 gTheoretical yield of sodium sulfate = 131.13 gPercentage yield =?

Percentage yield = (Actual /Theoretical) × 100

Percentage yield = (122.4 / 131.13) × 100

Percentage yield = 93.3%

Thus, the percentage yield is 93.3%

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Use the periodic table or graphic in lesson. Choose the correct electron configuration of carbon. 1s 22s 22p 4 1s 22s 22p 2 1s 22s 22p 1 1s 22s 12p 2

Answers

The Correct electron configuration of carbon as 1s² 2s² 2p². Option B.

To understand why this is the correct electron configuration, let's break it down step by step:

The atomic number of carbon is 6, which means it has six electrons. Electrons are distributed in energy levels or shells around the nucleus.

The first shell, known as the 1s orbital, can hold a maximum of 2 electrons. Therefore, the first part of the electron configuration is 1s², indicating that two electrons occupy the 1s orbital.

The second shell has two subshells: the 2s orbital and the 2p orbital. The 2s orbital can hold a maximum of 2 electrons, while the 2p orbital can hold a maximum of 6 electrons. In the case of carbon, after the 1s orbital, two more electrons occupy the 2s orbital. So far, we have 1s² 2s².

The remaining two electrons in carbon are placed in the 2p orbital. The 2p orbital consists of three separate p orbitals: 2px, 2py, and 2pz. Each p orbital can hold a maximum of 2 electrons. Therefore, the last part of the electron configuration for carbon is 2p², indicating that two electrons occupy the 2px and 2py orbitals. Option B is correct.

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A population of plants has a mixture of individuals with short, wide flowers and long, narrow flowers. Short, wide flowers are more easily pollinated by bees while long, narrow flowers are more easily pollinated by hummingbirds. Over time, the population becomes dominated by long, narrow flowers.Which statement ,begin emphasis,best,end emphasis, explains the increase in number of plants with long, narrow flowers over time?Answer options with 4 options.The environment favors short, wide flowers instead of long, narrow flowers.B.The gene for short, wide flowers is mutated into a gene for long, narrow flowers.C.Individuals with long, narrow flowers are stronger than individuals with short, wide flowers.D.Individuals with long, narrow flowers produce more seeds than individuals with short, wide flowers.

Answers

The best explanation for the increase in the number of plants with long, narrow flowers over time is option D: Individuals with long, narrow flowers produce more seeds than individuals with short, wide flowers.

In this population, short, wide flowers are better suited for bee pollination, while long, narrow flowers are more suitable for hummingbird pollination. Over time, the plants with long, narrow flowers produce more seeds compared to those with short, wide flowers.

This happens because the hummingbirds, which are the main pollinators for long, narrow flowers, are more effective in transferring pollen between these flowers. As a result, the long, narrow flower individuals have a higher reproductive success and pass on their traits to the next generation

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Which can be excluded from a list of objects in the solar system.
Constellation
Sun
Planet
Asteroid belt

Answers

Constellations can be excluded from a list of objects in the solar system.

The correct option is A.

What is the solar system?

The solar system refers to the collection of celestial bodies that are gravitationally bound to the Sun. It consists of the Sun, the eight planets namely; Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, their moons, asteroids, comets, and other smaller objects.

While constellations are formations of stars as observed from Earth, they are not physical objects within the solar system itself.

The Sun, planets, and the asteroid belt, on the other hand, are all components of the solar system.

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What is the resource population of the weebugs?​

Answers

Insects from the genus Cimex known as bed bugs feast on blood, typically at night and skin rashes.

Thus, Their bites can have a variety of negative health repercussions, such as skin rashes, emotional effects, and allergy symptoms.  

The effects of bed bug bites on the skin might range from little redness to obvious blisters.  Itching is typically prevalent, and symptoms might take anywhere from minutes to days to manifest.  

Some people might experience fatigue or a fever. Usually, impacted bodily parts are those that are exposed. There is no known contagious disease that their bites can spread.Vasculitis and regions of dead skin are unusual complications.

Thus, Insects from the genus Cimex known as bed bugs feast on blood, typically at night and skin rashes.

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Sally wrote a paragraph about how the carbon cycle might be affected near a volcano. Select the word for each blank to complete her sentences.
Close to the volcano, the carbon dioxide levels could
. This could be good for
, because they require carbon dioxide to grow. Over thousands of years when these organism decay, they could form more
. This part of the carbon cycle is an example of how carbon from the
is used by organisms that eventually become part of the
.
Previous Next

Answers

To complete Sally's paragraph of the carbon cycle, the correct words to fill in the blanks are:

increaseplantslimestoneatmosphere

How does carbon cycle work?

Close to the volcano, the carbon dioxide levels could increase. This could be good for plants, because they require carbon dioxide to grow. Over thousands of years when these organisms decay, they could form more limestone. This part of the carbon cycle is an example of how carbon from the atmosphere is used by organisms that eventually become part of the lithosphere.

The carbon cycle is a biogeochemical cycle that describes the movement of carbon through the biosphere, geosphere, hydrosphere, and atmosphere. The carbon cycle is one of the most important cycles on Earth, as it is essential for life.

In the paragraph, Sally is describing how the carbon cycle can be affected by volcanoes. When a volcano erupts, it releases carbon dioxide into the atmosphere. This can increase the carbon dioxide levels in the atmosphere, which can be good for plants. Plants use carbon dioxide to photosynthesize, which is the process by which they convert sunlight into energy.

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Determine the volume of Hydrogen gas collected over water from the reaction of
25.6g of Magnesium reacting with 45.0g of Hydrochloric acid to make magnesium
chloride and hydrogen gas. The gas is collected at 785.4 torr and 36.5 C. The vapor
pressure of water at 36.5C is 47.1 mmHg.

Answers

The volume of hydrogen gas collected over water is approximately 25.10 liters. We need to consider the stoichiometry of the reaction, the ideal gas law, and the partial pressure of hydrogen gas.

First, let's balance the equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl):

Mg + 2HCl -> MgCl₂ + H₂

From the balanced equation, we can see that 1 mole of magnesium reacts to produce 1 mole of hydrogen gas.

1. Calculate the number of moles of magnesium (Mg):

Molar mass of Mg = 24.31 g/mol

Number of moles of Mg = Mass of Mg / Molar mass of Mg = 25.6 g / 24.31 g/mol = 1.054 mol

2. Calculate the number of moles of hydrogen gas (H₂):

Number of moles of H₂ = Number of moles of Mg = 1.054 mol

3. Apply the ideal gas law to calculate the volume of hydrogen gas (V₂):

PV = nRT

Given:

Pressure (P) = 785.4 torr

Temperature (T) = 36.5 °C = 36.5 + 273.15 K = 309.65 K

R = 0.0821 L·atm/(mol·K) (gas constant)

Number of moles (n) = 1.054 mol

Convert the pressure to atm:

785.4 torr = 785.4 torr * (1 atm / 760 torr) = 1.032 atm

Substituting the values into the ideal gas law equation:

V₂ = (nRT) / P = (1.054 mol * 0.0821 L·atm/(mol·K) * 309.65 K) / 1.032 atm ≈ 25.10 L

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Balance the below equations:
Mg + O₂ → MgO
Al + O₂ → Al₂O3​

Answers

you can use this method to balance any equation,

write you elements down , then start balancing them one after the other,

starting from metals , to non metals

it's better to balance hydrogen and oxygen the last and in most cases , they are automatically balanced

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Calculate the pH after 0.020 mole of NaOH is added to 1.00 L of a mixture containing 0.100 M HONH₂ and 0.100 M HONH3CI.
Select one:
a. 6.22
b. 6.04
c. 5.44
d. 12.30​

Answers

The pH of the solution is 6.04. The correct option is B

To solve this problem

The pH of a solution is a measure of its acidity or alkalinity. A pH of 7.0 is neutral, a pH below 7.0 is acidic, and a pH above 7.0 is alkaline.

A solution of HONH2 and HONH3CI reacts with the addition of NaOH to produce HONH2 and NaCl. The solution becomes more alkaline as a result of this reaction because it contains more HONH2.

The pH of the solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([HONH2]/[HONH3Cl])

The pKa of HONH₂ is 5.97. The concentrations of HONH₂ and HONH3CI in the solution are 0.100 M and 0.080 M, respectively.

Substituting these values into the Henderson-Hasselbalch equation, we get:

pH = 5.97 + log(0.100/0.080) = 6.04

Therefore, the pH of the solution is 6.04.

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Calculate the pH after 0.2 mole of HCI is added to 1.00 L of a solution that is 1.00 M HNO₂ and 1.00 M NaNO2.
Select one:
a. 3.48
b. 3.22
c. 3.33
d. 2.33​

Answers

A weak acid (or base) and its corresponding conjugate base (or acid) make up a buffer solution. If only a modest amount of base or acid is supplied, it can withstand pH fluctuations. pH of the solution is 3.48 .

Thus, The Henderson-Hasselbalch equation can be used to express the pH of a buffer solution.

The pH scale gauges a substance's acidity or basicity. The pH scale has numbers 0 through 14. Seven is the neutral pH. Acidic conditions have a pH under 7. More than 7 pH is considered basic.

Each whole pH number below 7 is ten times more acidic than the next higher value since the pH scale is logarithmic. For instance, pH 4 is 100 times (10 times 10) more acidic than pH 6, while pH 5 is ten times (10 times) more acidic than pH 4.

Thus, A weak acid (or base) and its corresponding conjugate base (or acid) make up a buffer solution. If only a modest amount of base or acid is supplied, it can withstand pH fluctuations. pH of the solution is 3.48 .

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if scientists found a fossil in the middle layer that was 2 million years old, would they think Earth was more or less than 2 million years

Answers

The discovery of a 2-million-year-old fossil would align with the existing understanding of Earth's geological history, as it falls within the timeframe of the Quaternary period.

If scientists found a fossil in the middle layer that was determined to be 2 million years old, they would not automatically conclude that Earth was younger or older than 2 million years. The age of the fossil would provide valuable information about the minimum age of the layer in which it was found, but it would not necessarily provide conclusive evidence about the age of the entire Earth.

To determine the age of Earth, scientists rely on a variety of dating methods, including radiometric dating of rocks and minerals, as well as the study of isotopes and geological processes. These methods provide estimates of Earth's age in the billions of years.However, it would not significantly alter the prevailing scientific consensus that Earth is approximately 4.5 billion years old. The age of Earth is based on a comprehensive body of evidence from multiple disciplines and dating techniques, and a single fossil would not overturn that understanding.

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During the life of the investment annual net income and net annual cash flows are expected to be $17.689 and 549,000, respectively. Sheridan has a 12% cost of capital rate, which is the required rate of return on the investment Click here to view PV table site the cash payback period. (Round answer to 1 decimal place, c3, 10.5.) Cash payback period 2 years Compute the annual rate of return on the proposed capital expenditure (Round answer to 2 decimal places, e.g. 10.52%) Annual rate of return X (b) Question 2 of 2 113 = Compute the cash payback period (Round answer to 1 decimal place, e.g. 10.5.) Cash payback period years Compute the annual rate of return on the proposed capital expenditure (Round answer to 2 decimal places. c.9. 10.52%) Annual rate of return % (b) Using the discounted cash flow technique, compute the net present value. (If the net present value is negative, use either a negative sign preceding the number e-s, 45 or parentheses es (45). 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